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Remove const from as_if::operator()() return (#425)

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Returning a const value prevents the use of non-copyable return types
such as unique_ptr.
This commit is contained in:
Victor Mataré
2016-11-11 06:29:41 +01:00
committed by Jesse Beder
parent 96598c5c25
commit 994cf97b59
1 changed files with 3 additions and 3 deletions
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6
include/yaml-cpp/node/impl.h
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@@ -103,7 +103,7 @@ struct as_if<std::string, S> {
explicit as_if(const Node& node_) : node(node_) {}
const Node& node;
const std::string operator()(const S& fallback) const {
std::string operator()(const S& fallback) const {
if (node.Type() != NodeType::Scalar)
return fallback;
return node.Scalar();
@@ -115,7 +115,7 @@ struct as_if<T, void> {
explicit as_if(const Node& node_) : node(node_) {}
const Node& node;
const T operator()() const {
T operator()() const {
if (!node.m_pNode)
throw TypedBadConversion<T>(node.Mark());
@@ -131,7 +131,7 @@ struct as_if<std::string, void> {
explicit as_if(const Node& node_) : node(node_) {}
const Node& node;
const std::string operator()() const {
std::string operator()() const {
if (node.Type() != NodeType::Scalar)
throw TypedBadConversion<std::string>(node.Mark());
return node.Scalar();