Converted indexing to std::size_t, and fixed the Node templated overloads to properly index any index type (determining what is an index type is a bit of a hack - it should be is_convertible<T, std::size_t> (I think), but I just explicitly wrote down a list)

This commit is contained in:
Jesse Beder
2009-08-19 20:58:07 +00:00
parent ba11f5ae15
commit 81c2e6b6ca
17 changed files with 134 additions and 78 deletions

60
include/nodeutil.h Normal file
View File

@@ -0,0 +1,60 @@
#pragma once
#ifndef NODEUTIL_H_62B23520_7C8E_11DE_8A39_0800200C9A66
#define NODEUTIL_H_62B23520_7C8E_11DE_8A39_0800200C9A66
namespace YAML
{
template <typename T, typename U>
struct is_same_type {
enum { value = false };
};
template <typename T>
struct is_same_type<T, T> {
enum { value = true };
};
template <typename T, bool check>
struct is_index_type_with_check {
enum { value = false };
};
template <> struct is_index_type_with_check<std::size_t, false> { enum { value = true }; };
#define MAKE_INDEX_TYPE(Type) \
template <> struct is_index_type_with_check<Type, is_same_type<Type, std::size_t>::value> { enum { value = true }; }
MAKE_INDEX_TYPE(int);
MAKE_INDEX_TYPE(unsigned);
MAKE_INDEX_TYPE(short);
MAKE_INDEX_TYPE(unsigned short);
MAKE_INDEX_TYPE(long);
MAKE_INDEX_TYPE(unsigned long);
#undef MAKE_INDEX_TYPE;
template <typename T>
struct is_index_type: public is_index_type_with_check<T, false> {};
// messing around with template stuff to get the right overload for operator [] for a sequence
template <typename T, bool b>
struct _FindFromNodeAtIndex {
const Node *pRet;
_FindFromNodeAtIndex(const Node&, const T&): pRet(0) {}
};
template <typename T>
struct _FindFromNodeAtIndex<T, true> {
const Node *pRet;
_FindFromNodeAtIndex(const Node& node, const T& key): pRet(node.FindAtIndex(static_cast<std::size_t>(key))) {}
};
template <typename T>
inline const Node *FindFromNodeAtIndex(const Node& node, const T& key) {
return _FindFromNodeAtIndex<T, is_index_type<T>::value>(node, key).pRet;
}
}
#endif // NODEUTIL_H_62B23520_7C8E_11DE_8A39_0800200C9A66